Mereja.Forum

[Thomas H]

[Thomas H]

Is this true ?

[Temt]

ሚዛን ከልቢ ፲፯ ኪሎ፡(ንኸብደይ ጥራይ ከም ቮድካቸው)
ሚዛን ድሙ ፯ ኪሎ፡(ፈርጣዕ ከም ሽርጡ aka "Kerenite")
ሚዛን ኣንጭዋ ፫ ኪሎ (ሓባጥ ከም ኣቢቹ - መደናገሪ)

ድምር ናይ ሰለስቲኦም ጐሓላሉ፡ ፩፯+፯+፫= ፳፯ ኪሎግራም

[eden]

10+20+24
=54
= 54/2
=27

[Dark Energy]

What is that ? Elementary Schoo Math !
Let y be weight of the cat
Let X be the weight of the mouse
Let Z be the weight of the dog
Suppose the life of the dog depends on the life of the cat. dz/dy and the life mouse is dy/dx.
Suppose the cat lives to be 100 years old. How long would the dog and the mouse live respectively before their life is sniffed out of them ? BTW, this is very basic CAL.
BTW, the boundary conditions are given . X , Y, Z are all greater than zero. Meaning , they have had life. Is this possible to figure out in what century they lived ? No, you need more info for that. That would be your next assignment.

[Sam Ebalalehu]

I do not think the question is right. If the mouse and cat weigh 10 kilograms either the mouse weighs two kilograms or 4 kilograms. Because the dog is weighed with both, we should figure out how much it weighs. But I tried I could not. If we cannot figure out how much the dog weighs, we could not add the three to get their total weight.

[Thomas H]

Temt,
Please use time efficiently. I know that strong time management skills don't come naturally to everyone. Time efficiency is about working quickly while delivering high-quality results. It's about staying focused, working productively, and getting the job done well without wasting time. You answered the question 4 hours after I posted it. I was at the airport when I posted the question and after 4 hours flight I arrived at Punta Cana (Dominican Republic) and when I checked ER forum I saw your answer. 27KG is the correct answer,but it took you long to answer it so it doesn't count. Shame on you !

Eden is also correct. Unlike Temt Eden answered the question as soon as he saw it with in reasonable time. Good job Eden!


FINAL ANSWER
Mouse 3KG
Cat 7KG
Dog 17KG

[Naga Tuma]

10+20+24
=54
= 54/2
=27

eden,

That is a clever way to solve it. It took me a few minutes.

I am not sure if there are any elementary school students who read this forum. They would benefit if you explained how you solved it, spotting each twice and dividing the total by 2. Correct?

Here may be a good algebra for elementary or high school students.

a+b = 10 —> b = 10-a
b+c = 20 —> 10-a+c = 20 —> -a+c = 10 (1)
a+c = 24 (2)

Solving 1 and 2 simultaneously:

-a+c = 10
a+c = 24
2c = 34 —> c = 17
-a+17 = 10 —> a = 7
b = 10 -7 = 3
a + b + c = 7 + 3 + 17 = 27

This illustration of how to solve it is for interested students in some elementary algebra.

I still remember how exhilarated I was sometime after starting school after solving a challenging math question for my age at that time. One of my older brothers brought the following question home and asked it at a dinner time.

Someone who had 20 Birrs wanted to buy 20 animals, mules for four Birrs each, horses for fifty cents each, and donkeys for twenty five cents each.

Solving that question by trial and error so early in school has stayed with me ever since.